100x-50x^2=0

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Solution for 100x-50x^2=0 equation:



100x-50x^2=0
a = -50; b = 100; c = 0;
Δ = b2-4ac
Δ = 1002-4·(-50)·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100}{2*-50}=\frac{-200}{-100} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100}{2*-50}=\frac{0}{-100} =0 $

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